Math, asked by notwolfdavid, 1 month ago

In the adjacent figure that, CPllAB, then <ACB is
(A) 70°
(b) 65
(c) 75
(D) 60°

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Answers

Answered by brainliest80

2

Answer:

75°(c)

Step-by-step explanation:

<BAC = <ACP = 40°

<ACP+<ACB+<PCD=180°(Linear pair)

40°+<ACB+65°=180°

105°+<ACB=180°

<ACB=180°-105°=75°

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