In the adjoining fig. line BD&AS intersect each other at point P. m< ABP=34° then find m< APD & m
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∠APD and ∠APB are angles in a linear pair.
∴m∠APD + m∠APB = 180° ∴47 + m∠APB = 180
∴47 + m∠APB – 47 = 180 – 47 …. (Subtracting 47 from both sides)
∴m∠APB = 133° m∠CPD = m∠APB = 133° … .(Vertically opposite angles) m∠BPC = m∠APD = 47° … .(Vertically opposite angles)
∴The measures of ∠APB, ∠BPC and ∠CPD are 133° , 47° and 133° respectively
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