Question

In the adjoining figare 'o' is the centre of circle. Find the 'a' and 'b'​

Answer 1

Here, angle TRS =90° (triangle in the semi circle)

angle RES+ angle RTS = 180° (cyclic quadrilateral)

angle RTS = 180° -150°

angle RTS = 30°= a

In triangle RTS,

a + b + 90° = 180° ( angle sum property of triangle)

b = 180°- 120°

b= 60°

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Answer 2

✰Step-by-step explanation:

In the adjoining figure,

O is the center of circle.

★Given →

angle RES = 150°

★ To find→

Value of angle RTS (a) and angle RST( b).

★Solution→

TS is the diameter of the circle.

So,

angle TRS = 90° [ Semicircle angle]

angle RES + angle RTS = 180°

[The sum of the opposite angles to the equator is 180 degrees.]

➪150° + a = 180°

➪a = 180° - 150°

➪a = 30°

• ∆RTS is a triangle.

angle ( TRS + RTS + RST) = 180°

[ The sum of the three angles of the triangle is 180 degrees.]

➪ 90° + 30° + b = 180°

➪ b= 180° - 120°

➪ b= 60°

★ Answer→

a = 30°

b = 60°