Question

In the adjoining figure, a chord AB of a circle of radius 10 cm
subtends a right angle at the centre O. Find the area of the
sector OACB and of the major segment. Take a = 3.14.[[{(only 1 question here I have,how triangle area is 50cm square)}]]​

Answer 1

Step-by-step explanation:

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Answer 2

As we know that,

Area of Sector = $\huge{\bf \it \frac{\pi r^2 \theta}{360\degree}}$

Here, Given:-

• Φ = 90°
• π = 3.14
• r = 10 cm

Therefore,

Area of the sector OACB :-

$\implies \frac{3.14 \times (10)^2 \times 90°}{360°}$

$\implies \bf \red{78.5 cm^2}$

Hence, the area of the sector OACB is 78.5 cm^2