In the adjoining figure a semicircle with its diameter on hypotenuse of right angle triangle which is touching the remaining sides of a triangle with centre o if length ao is equal to 15 centimetre and bo is equal to 20 find the radius of the semicircle.
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Answer:
In △ABC AB=AC
⇒∠B=∠C (Angles opposite to equal sides are equal)
Now using angle sum property
∠A+∠B+∠C=180
∘
⇒80
∘
+∠C+∠C=180
∘
⇒2∠C=180
∘
−80
∘
⇒∠C=
2
100
∘
=50
∘
now ∠C+∠x=180
∘
(Angles made on straight line (AC) are supplementary)
⇒50
∘
+∠x=180
∘
⇒∠x=180
∘
−50
∘
=130
∘
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