Question

In the adjoining figure, AABC is an isosceles triangle in which
43 = 4C and AD is a median.
Prove that
() ADB=AADC
(62) BAD = _CAD​

Answer 1

Answer:

△ABD and △ACD

AB=AC (given )

Then ∠ABD=∠ACD ( because AB=AC )

and ∠ADB=∠ADC=90( because AD⊥BC )

∴△ABD=△ACD

∠BAD=∠CAD

It is defective to use ∠ABD=∠ACD for proving this result