Question

In the adjoining figure, AABC is an isosceles triangle in which AB = AC.
If BM I AC and CN 1 AB, prove that :
(i) ABMC ACNB
ho
(ii) BM = CN​

Answer 1

Step-by-step explanation:

In ∆ABC

AB=AC

so, <ABC= <ACB

or, <NBC= <MCB---------a)

Now, in right∆CNB and ∆BMC

<NBC=MCB. (from---a)

<CNB=<BMC. (each=90°)

and BC=BC. (common)

therefore, ∆BMC=~∆CNB

BM=CN (by CPCT)

@WildCat7083