In the adjoining figure AB=BC . Find the value of x and y
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Angle CAB=Angle ACB = 65 (Angles opposite to equal sides are equal )
Angle CAB +Angle ACB +Angle CBA = 180 (Triangle ABC)
=65+65+y =180
=y+130=180
=y=180-130
=y=50
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Angle ACB +Angle ACD=180(linear pair)
=65+Angle ACD=180
=Angle ACD=180-65
=Angle ACD= 115
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Angle DAC+Angle ACD+Angle ADC=180 (triangle ADC)
=50+115+x=180
=x+165=180
=x=15
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