Question

in the adjoining figure ab is a diameter, ac is a chord and oc is a radius of a circle such that angle bac=30 degree. find angle ocb.

PLS SOLVE THIS QUESTION.​

Answer 1

Answer:

Step-by-step explanation:

OA = OB =OC(RADIUS)

∠BAC = ∠OCB = 30 ( OPPOSITE SIDES OF EQUAL ANGLES ARE EQUAL)

Answer 2

Answer:

Step-by-step explanation:

Angle ACB=90°(Angle on the

semicircle is 90°)-(1)

In triangle AOC,

AO=OC(Radii of same circle)

Therefore , according to the isoceles triangle property

Angle OAC= Angle OCA=30°-(2)

Angle ACB= Angle ACO+Angle OCB

90°=30°+ Angle OCB. [From (1)&(2)]

Angle OCB=60°

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