Question

In the adjoining figure, AB is a diameter of a circle with centre O. If chord AC = chord AD, prove that arc BC = arc DB.

Answer 1

Hope it is helpful.....

Answer 2

Arc BC = Arc BD.

Explanation:

Given: In a circle with center O, AB is the diameter. AC and AD are chords that are equal.

To prove: Arc BC = Arc BD

Join BC and BD.

In right-angled triangle ABC and triangle ABD, AB is common. Given that AC = AD.

So triangle ABC is congruent to triangle ABD.

So the corresponding sides will be equal.

BC will be equal to BD.

So the corresponding Arc BC = Arc BD.

Hence proved.