In the adjoining figure AB is a line and
AOE = BOE = COD. If AOC = 45°
Find
1) EOC
2) BOC
Attachments:
Answers
Answered by
0
Answer:
AOE + BOE = 180...... linear pair
AOE = BOE
1/2 × 180 = AOE & BOE
AOE=BOE= 90
:. EOC = AOE + AOE
EOC = 90 + 45
= 135
:. BOC = EOC
BOC = 135
Answered by
0
Question :-
In figure, lines AB and CD intersect at 0. If ∠AOC + ∠BOE = 70° and ∠BOD = 40°, find ∠BOE and reflex ∠COE.
Answer :-
Since AB is a straight line,
∴ ∠AOC + ∠COE + ∠EOB = 180°
o r (∠AOC + ∠BOE) + ∠COE = 180° or 70° + ∠COE = 180° [ ∵∠AOC + ∠BOE = 70° (Given)]
or ∠COE = 180° – 70° = 110°
∴ Reflex ∠COE = 360° – 110° = 250°
Also, AB and CD intersect at O.
∴∠COA = ∠BOD [Vertically opposite angles]
But ∠BOD = 40° [Given]
∴ ∠COA = 40°
Also, ∠AOC + ∠BOE = 70°
∴ 40° + ∠BOE = 70° or ∠BOE = 70° -40° = 30°
Thus, ∠BOE = 30° and reflex ∠COE = 250°.
Plz mrk as brainliest ❤
Similar questions