In the adjoining figure, AB ll CD ll EF and PQ ll RS. If angle RQD = 25⁰, then angle QRS is equal to...?
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Step-by-step explanation:
Given figure, if AB || CD || EF, PQ || RS, RQD=25o and CQP=60o,
Then ∠SRB=∠CQP=60
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OR ∠QRA=∠RQD=25
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So ∠ARS+∠SRB=180
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∴∠ARS=120−60=120
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∠QRS=∠ARS+∠QRA=120+25=145
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