Question

In the adjoining figure. ABC is right triangled at LA
and AB = AC. Bisector of ZA meets BC at D.
Prove that BC = 2AD


Please solve it and u will get 100 points

Answer 1

Answer:

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Step-by-step explanation:

In triangle  , ABC right angled at A and AB = AC 

 ∠ A = ∠ B 

Sum of angles of a triangle = 180º 

∠A+ ∠B+ ∠C=180º 

90º+∠B+∠B=180º 

2∠B=180º -90º 

2∠B=90º 

∠B=45º (1)

since  AD is the bisector of BAC 

∠BAD = ∠CAD = 90º/2 = 45º (2)

then, ∠BAD = ∠ABC 

AD = BD (3)

Similarly ∠ CAD = ∠ ACD 

So, AD = DC (4)

adding equation (3) and (4) 

We get, AD + AD = BD+DC 

hence, 2AD = BC 

Answer 2

Answer:

Here

bc is 2ad because it is a right angle Triangle