Question

In the adjoining figure ABCD in a parallelogram CE AB and BF AD of Ab 18 cm ad 12cm and ce 10 cm find ad​

Answer 1

Answer:

Step-by-step explanation:

BF=9.6cm

base=AB=12cm

height=CE=8cm

Area of parallelogram=Base*Height

                                     =12*8

                                     =96cm^2

base=AD=10cm

height=BF

Area of parallelogram= base*height

                               96=10*height

                               96/10=height

                              9.6cm=height

Hence BF=9.6cm

Answer 2

Answer:

In parallelogram ABCD, we have given AB=10cm, AE=8cm, and CF=12cm.

⇒ AB=DC=10cm [Opposite sides of parallelogram are equal]

⇒ Lets find out area of parallelogram with height AE and base DC.

⇒ Area of parallelogram ABCD=b×h

⇒ Area of parallelogram ABCD=DC×AE

⇒ 10×8

∴ Area of parallelogram ABCD=80cm

2

--- ( 1 )

⇒ Now, to find area of parallelogram let CF be the height and AD will be base.

⇒ Area of parallelogram ABCD=CF×AD

⇒ 80=12×AD [From ( 1 )]

⇒ AD=

12

80

∴ AD=6.66cm