Question

In the adjoining figure, ABCD is a parallelogram and AX||CY. Prove
that:
(i) AX = CY
(ii) AXCY is a parallelogram.​

Answer 1

Answer:

Here it is with explanation...

Answer 2

Answer:

prove AX=CY And AXCY is a ||gm

Step-by-step explanation:

Lit,

the mid point is M

(I) In ∆AMY and CMY, use know

∆AMX and ∆CMY is equal

MA=MC

=>MD-DY=MB-BX

=>MY=MX

∆AMX=~∆CMY

So, AX=CY [proved]

(II) In AMX and CMY

AX=CY (I)

AM=MC {common}

In YMA and CMX

AY=CX

MY=MX

So, AXCY is a||gm [proved]