In the adjoining figure ABCD is a parallelogram in which p is the midpoint of DC and q is a point on ac such that CQ =1/4 AC Also PQ when produced meet BC at R Prove that R is the midpoint of BC
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Asked on December 26, 2019 by
Shivu Jawaid
A parallelogram ABCD has P the mid- point of DC and Q intersects AC such that CQ=
4
1
AC. PQ produced meets BC at R prove that :
(a) R is the mid-point of BC
(b) PR=
2
1
DB
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ANSWER
Given ABCD is a parallelogram and P is midpoint of DC
also, CQ=
4
1
AC
To Prove : R is mid point of BC
Proof : Now
OC=
2
1
AC (Diagonals of parallelogram bisect each other) ...(i)
and CD=
4
1
AC ...(ii)
From (i) and (ii)
CD=
2
1
OC
In ΔDCO P and Q are midpoint of DC and OC Respectively
∴PQ∥DO
Also in ΔCOB Q is midpoint of OC and PQ∥DB
∴R is midpoint of BC
∴ in ΔABCPR∥DB
CD
CP
=
CB
CR
=
BD
PR
DB
PR
=
2
1
∴PR=
2
1
DB