Question

In the adjoining figure, ABCD is a quadrilateral
in which BN and DM are drawn perpendiculars
to AC such that BN = DM. If OB = 4 cm, then
BD is





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Answer 1

Answer:

ANSWER

GivenABCD is a quadrilateral in which diagonals AC and BD intersect each other at P

Also,DN⊥AC and BM⊥AC

DN=BM

In △DNP and △BMP we have

∠DPN=∠BPM since they are vertically opposite angles.

∠DNP=∠BMP since each are equal to 90

∘

DN=BM(given)

⇒△DNP≅△BMP by AAS postulate.

⇒DP=BP=8cms by CPCT

We have BD=BP+DP=8+8=16cms from the diagram.