Question

In the adjoining figure, ABCD is a quadrilateral. The bisector of A and meet at Determine​

Answer 1

[∠A+∠B+∠C+∠D=360

(propertyofQuadrilateral)

∠A+∠B+100=360

2∠PAB+2∠PBA=260

∠PAB+∠PBA=130

inΔABP

∠PAB+∠PBA+∠APB=180

130+∠APB=180

∠APB=180

−130

=50

Answer 2

∠A+∠B+∠C+∠D=360

(Property Of Quadrilateral)

∠A+∠B+100=360

2∠PAB+2∠PBA=260

∠PAB+∠PBA=130

in ΔABP

∠PAB+∠PBA+∠APB=180

130+∠APB=180

∠APB=180 −130

=50