In the adjoining figure ABCD is a rectangle and diagonals intersect at O. If angleABO=180, find i)angleABO ii)angleADO iii)angleOCB
AadarshaG:
Angle ABO can't be 180° 'cause the angle is formed between a diagonal and a side of a rectangule
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ABO can't be 180° .please write the exact question.ABO=45°.ADO=45°and OCD=45° all angles are bisectors of 90°
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angle ABO=angle ADO= angle OCB=45°
as all angles 90 bisector bisect them into half
as all angles 90 bisector bisect them into half
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