Question

in the adjoining figure ABCD is a rectangle in which ab=18 cm, bc=8 cm and de=10 cm find the area of the shaded region ebcd​

Answer 1

Given :-  

ABCD is a rectangle in which ab=18 cm, bc=8 cm and de=10 cm .

To find :-

The area of the shaded region ebcd​.

Solution:-

$AE = \sqrt{10^2 - 8^2} = \sqrt{100 - 64} = \sqrt{36} = 6 \\ \\ \\Area of Trapezium = \frac{1}{2} \times (sum \ of \ parallel \ sides ) \times (distance \ between \ them)\\ \\ \\ = \frac{1}{2} \times (18+12) \times 8 = 120 \ cm^2 \\ \\ \\ \\Hence,\ ans \ is 120.$

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Answer 2

Answer:

120cm^2

Step-by-step explanation:

SOLUTION -

$\sqrt{ {10 }^{2} } - {8 }^{2} \\ = \sqrt{100 - 64 } \\ = \sqrt{36} \\ 6 \\ area \: of \: trapezium \: = 1 \div 2 \times (b1 + b2) \times (height) \\ 1 \div 2 \times( 18 + 12) \times 8 \\ {120cm}^{2}$

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