In the adjoining figure ABCD is a rhombus. Find the values of x and y. Also find the all the angles of the rhombus.
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FIRSTLY , RHOMBUS IS A TYPE OF //GM.
<AOD = 90*.........diagonals of a rhombus are perpendicular bisectors.
so <x = 180*- 50-90*= 40*
Now,
< OAB = 40*.
so < y = 60*.
now < ACD= <Y = 60*........ ( < SUBTENDED FROM SAME BASE AND BETWEEN AD// CB )
< D = 40* + 40* = 80*.
< B= < D = 80*.......( opposite < of a //gm)
<A= 180*- <B = 100*....... (SUM OF ADJACENT < = 180*)
<C = < A = 100*
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<AOD = 90*.........diagonals of a rhombus are perpendicular bisectors.
so <x = 180*- 50-90*= 40*
Now,
< OAB = 40*.
so < y = 60*.
now < ACD= <Y = 60*........ ( < SUBTENDED FROM SAME BASE AND BETWEEN AD// CB )
< D = 40* + 40* = 80*.
< B= < D = 80*.......( opposite < of a //gm)
<A= 180*- <B = 100*....... (SUM OF ADJACENT < = 180*)
<C = < A = 100*
HOPE IT WILL HELP YOU. . . . . . . . . . .
PLZ MARK MY ANSWER AS BRAINLIEST AS SOON AS POSSIBLE! ! ! ! ! ! !
Hriday0102:
so < ADC = 80*
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