Question

In the adjoining figure , ABCD is a square . find the ratio between the circumferences the areas of the incircle and the circumcircle of the square

Answer 1

Answer:

Step-by-step explanation:

Let the side of Square be a cm

Diameter of incircle = side of Square = a

Radius of incircle =a/2 cm

Circumference = 2πr=2×π×a/2=π2

Diagonal of Square = diameter of circumcircle =√2a

Circumference of circumcircle =2π×√2a÷2( radius =√2a/2)

π√2a

Ratio of their circumference =π2/π√2a=1:√2

Ratio of their area =πr Square/πR Square =π×a Square ÷ 4/π×2a Square

=1:2