Question

in the adjoining figure, ABCD is a square with side 8 cm find the areas of triangles OAB, OBC, OCD and ODA ?​

Answer 1

Answer:

Area of the square = S×S

8×8=64

height of the triangle= 1/2×B×H=area of the traingle

=1/2×8×H=64

64/4=16

Hence, the height of the triangle is 16

Now, the area of triangle OAB=1/2×B×H

=1/2×8×16

=64

Now the area of OAB=64

Hence, the area of triangle OBC, OCD and ODA is also 64.

Hence the answer is 64 for all the traingle

Answer 2

Answer:

answer=64

Step-by-step explanation:

Area of square=s*s

8*8=64

height of triangle =1/2*B*H=Area of the triangle

1/2*8*H=64

64/4=16

Height of triangle is=16

Area of triangle=OAB=1/2*B*M

=1/2*8*16=64