Question

in the adjoining figure ABCD is a trapezium in which AB ll DC and AB = 2DC. then , the ratio of the area is​

Answer 1

Step-by-step explanation:

In triangle AOB and COD, we have

         ∠AOB=∠COD           [Vertically opposite angles]

and,  ∠OAB=∠OCD           [Alternate angles]

So, by AA-criterion of similarity, we have

    △AOB∼△COD

⇒ Area(△COD)Area(△AOB)=DC2AB2

⇒ Area(△COD)Area(△AOB)=(DC)2(2DC)2=14

Hence,  Area(△AOB):Area(△COD)=4:1

Hopes it helps♥️♥️