Question

In the adjoining figure, ∠B = ∠E, BD = CE and ∠1 = ∠2. Prove that ∆ABC ≅ ∆AED.

Answer 1

Answer:

yes

it is

thank you

Answer 2

∆ABC ≅ ∆AED.

Explanation:

Given: ∠B = ∠E, BD = CE and ∠1 = ∠2.

To Prove: ∆ABC ≅ ∆AED.

Proof:  

In ∆ABC and ∆AED, BD = CE (one pair of corresponding sides are equal)

∠B = ∠E and ∠1 = ∠2 (two pairs of corresponding angles are equal).

So ∆ABC is congruent to ∆AED.

Hence proved.

Please refer to the diagram for a clear idea of the sides and angles.