in the adjoining figure bo and co is are the bisector of of angle b and angle c respectively. if angle a = 50 degree then find angle BOC
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A+b+c = 180
50+b+c= 180
b+c = 130 ...(1)
divide equation (1) by 2
1/2(b+c) = 65....(2)
now in triangle obc
o+1/2(b+c) = 180
o+65= 180 ( from (2))
o= 180-65= 115
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