In the adjoining figure,DC|| Ab ,ad=BC.prove using the concept of congruent triangle that ae =bf
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IN THE ADJACENT FIGURE
DECF IS ARECTANGLE SO DE=CF⇒1
AS,DC||Ab,AB IS A TRANSVERSALSO ANGLE AED=ANGLEBFC⇒2GIVEN AD=BC⇒3
FROM1,2,3
BY RHS congruency
triangleAED=TRIangleDFC
BY CPCT
ae =bf
DECF IS ARECTANGLE SO DE=CF⇒1
AS,DC||Ab,AB IS A TRANSVERSALSO ANGLE AED=ANGLEBFC⇒2GIVEN AD=BC⇒3
FROM1,2,3
BY RHS congruency
triangleAED=TRIangleDFC
BY CPCT
ae =bf
Answered by
0
In the given figure,
CDEF is a rectangle
so, DE=CF
and is given that AD=BC
and angle DEA= angle CFB
so, AE=FB
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