Math, asked by mjkin86151, 10 hours ago

In the adjoining figure DX =4 , DE= 8, FY =6, DF=12 .complete the following activity to prove that seg XY || seg EF​

Answers

Answered by Yoursenorita
3

QUESTION:

  • In the adjoining figure DX =4 , DE= 8, FY =6, DF=12 .complete the following activity to prove that seg XY || seg EF

GIVEN:

  • Given : DX = 4, DE = 8, FY = 6, DF = 12

To Find :

  • prove that seg XY ll seg EEF

Solution:

  • DX = 4
  • DE = 8
  • FY = 6
  • DF = 12

  • DY = DF - FY = 12 - 6 = 6 cm

  • XE = DE - DX = 8 - 4 = 4 cm

  • DX/XE = 4/4 = 1

  • DY/YF = 6/6 = 1

DX/XE = DY/YF = 1

Thale's theorem / BPT

  • If a line is drawn parallel to one side of a triangle intersecting the other two sides, then it divides the two sides in the same ratio.

Converse is also True

  • If a line divides any two sides of a triangle in the same ratio then the line must be parallel to the third side this is a Converse of Basic Proportionality theorem or Converse of Thales

As DX/XE = DY/YF = 1

=> XY || EF

  • QED

Hence Proved

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