In the adjoining figure DX =4 , DE= 8, FY =6, DF=12 .complete the following activity to prove that seg XY || seg EF
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QUESTION:
- In the adjoining figure DX =4 , DE= 8, FY =6, DF=12 .complete the following activity to prove that seg XY || seg EF
GIVEN:
- Given : DX = 4, DE = 8, FY = 6, DF = 12
To Find :
- prove that seg XY ll seg EEF
Solution:
- DX = 4
- DE = 8
- FY = 6
- DF = 12
- DY = DF - FY = 12 - 6 = 6 cm
- XE = DE - DX = 8 - 4 = 4 cm
- DX/XE = 4/4 = 1
- DY/YF = 6/6 = 1
DX/XE = DY/YF = 1
Thale's theorem / BPT
- If a line is drawn parallel to one side of a triangle intersecting the other two sides, then it divides the two sides in the same ratio.
Converse is also True
- If a line divides any two sides of a triangle in the same ratio then the line must be parallel to the third side this is a Converse of Basic Proportionality theorem or Converse of Thales
As DX/XE = DY/YF = 1
=> XY || EF
- QED
Hence Proved
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