Math, asked by rahulaisectda7272, 10 hours ago

The factors of (1-6z+9z²) are-
The factors of (1-6z+9z²) are-

Answers

Answered by abhaysingh6201592398

4

Answer:

$1 - 6z + 9 z^{2} \\ 1 - 3z - 3z + 9z ^{2} \\ 1(1 - 3z) - 3z(1 - 3z) \\ (1 - 3z)(1 - 3z) \\$

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