In the adjoining figure, EFGH is a parallelogram. If S and T are points on EH and FG respectively such that ES = 1/3 EH, GT = 1/3 FG. Prove that ETGS is a parallelogram.
Answers
Answered by
1
Answer:
The diagonal BO of parallelogram ABCD intersects the segment AE at F, where E is any point on BC.
In △AFD and △BFE,
⇒ ∠FAD=∠FEB [ Alternate angles ]
⇒ ∠AFD=∠BFE [ Vertically opposite angles ]
∴ △ADF∼△BFE [ By AA similarity ]
∴
FA
DF
=
EF
FB
⇒ DF×EF=FB×FA
Step-by-step explanation:
MARK AS BRANIST
Similar questions