Question

in the adjoining figure,find
1 <ACD
2<BAD​

Answer 1

Answer:

Angle ADC + Angle ADB = 180° (Linear Pair)

80° + Angle ADB = 180°

Angle ADB = 180° – 80°

Angle ADB = 100°

Angle CAD + Angle ACD = Angle ADB

60° + Angle ACD = 100°

Angle ACD = 100° – 60°

Angle ACD = 40°

In ∆ ABD,

Angle ADB + Angle ABD + Angle BAD = 180° (Angle Sum Property of ∆)

100° + 30° + Angle BAD = 180°

130° + Angle BAD = 180°

Angle BAD = 180° – 130°

Angle BAD = 50°

Angle ACD = 40° and Angle BAD = 50°.

Answer 2

Step-by-step explanation:

Sorry for bad handwriting