in the adjoining figure, find x+y+z
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x+90=180(angles on a straight line=180)
x=180-90=90
y+70=180(angles on a straight line=180)
y=180-70=110
let us imagine angle a near angle z.So,
a+90+70=180(sum of angles in a triangle=180)
a+160=180
a=180-160=20.
z+a=180(angles on a straight line =180)
z+20=180
z=180-20=160.
Please mark as brainliest if it's correct.
x=180-90=90
y+70=180(angles on a straight line=180)
y=180-70=110
let us imagine angle a near angle z.So,
a+90+70=180(sum of angles in a triangle=180)
a+160=180
a=180-160=20.
z+a=180(angles on a straight line =180)
z+20=180
z=180-20=160.
Please mark as brainliest if it's correct.
arpitshukla2:
no its answer is x+y+z = 360 degree
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23
I Hope it is correct
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answer is 360 degree
I have found only values of unknown angles that's it
I do not done their sum
add 90 degree, 160 degree and 110 degree
if it is correct please mark as brainaliest
yes it is a correct answer
plz mark as brainaliest
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