In the adjoining figure,if O is the cente of circumcircle of triangle ABC and angle AOC=110degree., Let us write by calculating , the value of angle ABC.
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Since it is given that ∠AOC = 110° and by the theorem:-
The angle formed at the centre of a circle by an arc, is double of the angle formed by the same arc at any point on circle.
Since APCB forms a cyclic quadrilateral and we know that sum of opposite sides of a cyclic quadrilateral is equal to 180°
⇒ ∠APC + ∠ABC = 180
⇒ ∠ABC = 180 – 55 = 125°
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