In the adjoining figure, if PA=10 cm, then find the perimeter of ∆PCD
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PA = PB = 10cm (Two tangents on the circle from an external point are equal in length.) If we carefully watch out we get to know that there are two tangents from C and two from D. So, PA +PB = 10cm +10cm =20cm = Perimeter of the triangle PCD. Hence the answer is 20cm.
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