Question

In the adjoining figure it is given that CE Parallel line BA angle BAC =80°and angle ECD=35° find Angle ACE ,angle ACB, angle ABC

Answer 1

Answer:

∠ACE  = 80°

∠ACB  = 65°

∠ABC  = 35°

Step-by-step explanation:

∠BAC = ∠ACE   (alternative angles)

=> ∠ACE  = 80°

∠ACB + ∠ACE + ∠ECD = 180°  ( straight line)

=> ∠ACB + 80° + 35° = 180°

=> ∠ACB  = 65°

∠ACB + ∠BAC + ∠ABC  = 180°  ( sum of angle of triangle)

=> 65° + 80° + ∠ABC  = 180°

=> ∠ABC  = 35°

Answer 2

Answer:

Angle ACE = 80°

Angle ACB = 65°

Angle ABC = 35°