in the adjoining figure, lines AB and CD intersect at F. if angle efa = angle afd and angle cfb =50°, find angle efc
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AFD=CFB..... (opposite angles)
so AFD=50°
also AFD=EFA..... (given)
so EFA=50°
since AFD + EFA + EFC=180°
(angles on a line)
so EFC=180°-50°-50°=80°
SO EFC=80°
so AFD=50°
also AFD=EFA..... (given)
so EFA=50°
since AFD + EFA + EFC=180°
(angles on a line)
so EFC=180°-50°-50°=80°
SO EFC=80°
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