integral zeros of the polynomial q(x)=(x+3)(x+7) are
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Answered by
81
Zeroes of q(x) = (x+3)(x+7)
Put q(x) = 0
⇒ (x+3)(x+7) = 0
⇒x = -3 or x = -7
zeroes are -3 and -7
Put q(x) = 0
⇒ (x+3)(x+7) = 0
⇒x = -3 or x = -7
zeroes are -3 and -7
Answered by
54
To find the zero put q(x)=0
→(x+3)(x+7)=0
→x+3=0 or x+7=0
→x=-3 or x=-7
since we require integers, and both are integers
So ans will be x=-3 & x=-7
→(x+3)(x+7)=0
→x+3=0 or x+7=0
→x=-3 or x=-7
since we require integers, and both are integers
So ans will be x=-3 & x=-7
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