in the adjoining figure O is the centre then the value of x is....
please tell me
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Answer:
x=70°
Step-by-step explanation:
Since the ∆OPQ and ∆OPR has two of its sides as the radius of the circle ( OQ, OP, OR) they are isosceles triangles..So the angles opposite to the equal sides (OQ, OP, OR) are equal. so 2y+80°=180°(angle sum property)
2y=180°-80°
2y=100°
y=100°/2=50°
and x = y + z ( where z is the two angles of the ∆OPQ, z=20° found out by the same method)
x =50°+20°=70°
there fore x equal to 70° is the answer..
hope it was helpful
good evening mate..
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