Question

in the adjoining figure p and q are two Points on equal sides ab and ac of an isosceles triangle abc such ap=aq
prove bq=cp​

Answer 1

Here is your answer.

In ∆APC and ∆AQB ,

AP = AQ { given }

angle A = angle A { common }

AB = AC { given or isosceles triangle.}

∆APC ~= ∆AQB { SAS RULE }

BQ = CP { C.P.C.T. }

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