Question

In the adjoining figure PA = BS then prove that : PQ=RS.​

Answer 1

Step-by-step explanation:

given, PA = BS

in above circle ,

OA = OB = Redius of the circle

also TQ = TR ( Because cord of the circle is QR & OT perpendicular to QR at T )

now in triangles 0TP & OTS

TP^2 = OP^2-OT^2 &

TS^2 = OS^2 - OT^2

OA+PA = OB+BS. ( PA=BS)

so,

TP = TS

PQ = RS