Question

In the adjoining figure, PQ, RS and TU are three coplanar lines. AB is the transversal intersecting the lines at X, Y and Z. If ZPXA=115º; ZUZX=65° and ZUZX + Z SYZ = 180° then show that PQ//RS and RS//TU​

Answer 1

Answer:

It has been given that a:b=3:2

Hence, let a=3x and b=2x

Here, a+b=180

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[linear angles]

⇒3x+2x=180

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⇒5x=180

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⇒x=

5

180

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⇒x=36

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∴a=3×x=3×36

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=108

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Also, PQ parallel to RS and line l is a transversal.

∴a=f ....[ Corresponding angles ]

⇒f=108

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