In the adjoining figure, PQR is a right angled triangle at Q. If PQ = 3 cm and PR = 6 cm, find ∠QPR and ∠PRQ.
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Explanation:
Here, angle QPR = 60° and angle PRQ = 30°. In place of sec and cosec you can also relate with cos and sin.
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∠QPR = 60°
∠PRQ = 30°
Explanation:
PQR is a right angled triangle at Q.PQ = 3 cm and PR = 6 cm
Find ∠QPR and ∠PRQ.
Sec ∠QPR = Hypotenuse / Adjacent = PR / PQ = 6 / 3 = 2
Sec 60° = 2
Therefore ∠QPR = 60°
Cosec ∠PRQ = Hypotenuse / Opposite = PR / PQ = 6 / 3 = 2
Cosec 30° = 2
Therefore ∠PRQ = 30°
Hence solved.
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