in the adjoining figure, PQR is a right angled triangle. Q=90 degree, QR=5cm and PR-PQ =1 cm. Find the values of sin P and sec P
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Given PR + QR = 25 , PQ = 5
PR be x. and QR = 25 - x
Pythagoras theorem ,PR2 = PQ2 + QR2
x2 = (5)2 + (25 - x)2
x2 = 25 + 625 + x2 - 50x
50x = 650
x = 13
PR = 13 cm
QR = (25 - 13) cm = 12 cm
sin r = QR/PR = 12/13
cos r = PQ/PR = 5/13
tan r = QR/PQ = 12/5
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