Question

Variation of pressure (P) with volume (V) for an ideal
monoatomic gas is shown in figure. The molar
specific heat of the gas in the process will be​

Answer 1

Explanation:

picture explains more clearly

Answer 2

Given:

Variation of pressure (P) with volume (V) for an ideal monoatomic gas is shown in figure.

To find:

Molar specific heat of the gas?

Calculation:

From the graph , we can say :

$\therefore \: P \propto {V}^{2}$

$\implies \: P{V}^{ - 2} = constant$

$\implies \: P{V}^{ n} = constant$

Now, let molar specific heat capacity be C:

$\therefore \: C = C_{v} + \dfrac{R}{1 - n}$

$\implies\: C = \dfrac{3R}{2} + \dfrac{R}{1 - ( - 2)}$

$\implies\: C = \dfrac{3R}{2} + \dfrac{R}{1 + 2}$

$\implies\: C = \dfrac{3R}{2} + \dfrac{R}{3}$

$\implies\: C = \dfrac{(9 + 2)R}{6}$

$\implies\: C = \dfrac{11R}{6}$

So, the heat capacity is 11R/6.