in the adjoining figure PR and QT are diameter of a circle with centre O line segment PQ and QR are joined end <ROT =106°
Find: angle PQR
angle PQR
m(arc QP)
Answers
Answer:
Angle PQR is 90 degree which is correct
Given : PR and QT are diameter of a circle with centre O line segment PQ and QR are joined end ∠ROT =106°
To Find : ∠PQR
m(arc QP)
Solution:
PR is diameter
Hence ∠PQR = 90° ( angle subtended by diameter at circle )
∠POQ = ∠ROT ( vertically opposite angles )
∠ROT =106°
=> ∠POQ =106°
m(arc QP) = ∠POQ
Hence m(arc QP) = 106°
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