In the adjoining figure, PT is tangent at point of the circle is the circumcenter of triangleABC. IfACP = 118° then measure of anglex is :2832°42°38°
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Answer:-
Join OC.
OC is the radius and Pt is the tangent to circle at point C
∴
O
C
⊥
P
T
∴
∠
O
C
P
=
90
0
given
∠
A
C
P
=
118
0
∴
∠
A
C
O
=
∠
A
C
P
−
∠
O
C
P
=
118
0
=
90
0
∠
A
C
O
=
28
0
Since O is the circumcentre, thus
O
A
=
O
C
(radius)
∴
∠
O
A
C
=
∠
O
C
A
∴
x
=
28
0
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