in the adjoining figure QR||RS find angle PSR
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It's 105 degrees
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Hope it helps :)
Pls mark as brainlyest:)
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Answered by
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Sorry Dear QR=RS.
By the way come to the solution.
Soln:
since QR=RS=x(let)
∴Acc. to Triangular law ∠RQS=∠RSQ
Now ∠QRS + ∠RSQ + ∠SQR =180
∴90 + x + x =180
2x+90=180
x = 45
∴∠QSR=45
Now ∠PSR= ∠PSQ + ∠QSR=60(Given) + 45
=105
By the way come to the solution.
Soln:
since QR=RS=x(let)
∴Acc. to Triangular law ∠RQS=∠RSQ
Now ∠QRS + ∠RSQ + ∠SQR =180
∴90 + x + x =180
2x+90=180
x = 45
∴∠QSR=45
Now ∠PSR= ∠PSQ + ∠QSR=60(Given) + 45
=105
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