In the adjoining figure the circles with centres p,q and r intersect at points b,c,d and e as shown.lines cb and ed intersect at point m
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In the adjoining figure the circles with centres p,q and r intersect at points b,c,d and e as shown.lines cb and ed intersect at point m
From figure it's clear that,
MA is a tangent
MC is a secant with center P.
Using the tangent - secant theorem, we get,
MA² = MB × MC ..............A
Similarly, we have,
MF is a tangent
ME is a secant with center R.
Using the tangent - secant theorem, we get,
MF² = MD × ME .............B
In Δ MCD and Δ MEB,
∠ MCD = ∠ MEB (angles inscribed from same arc)
∠ CMD = ∠ EMB (common angle)
∴ Δ MCD ~ Δ MEB ( using AA theorem criteria)
⇒ MC/ME = MD/MB (using C.S.S.T)
∴ MC × MB = MD × ME ...........C
Using A, B and C, we get,
MA² = MF²
∴ MA = MF
Similarly,
MC = ME
Therefore, it is proved that, CB and ED intersect at point M.
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