Question

. In the adjoining figure, three coplanar lines
AB,CD and EF intersect at a point O. Find the
value of x. Hence, find ZAOD, ZCOE and
ZAOE.
​

Answer 1

Answer:

x=18°   ∠ AOD=36°  ∠ COE=90°   ∠ AOE=54°

Step-by-step explanation:

We know that sum of angles in a circle =360°       ----1{eq}

also,

∠COE=∠DOF=5x    ∠EOA=∠BOF=3x    ∠BOC=∠AOD=2x  {vertically opp∠}

∴∠COE+∠DOF+∠EOA+∠BOF+∠BOC+∠AOD= 360° {form eq 1}

∴5x+5x+3x+3x+2x+2x=360°

⇒20x=360°

⇒x=$\frac{360}{20}$

∴x=18°

putting the value of x,

5x=90°

3x=54°

2x=26°

Please mark this as brainliest