Question

in the adjoining figure two lines ab and CD intersect each other at the point O such that BC parallel CA and BC is equals to DA. show that O is the midpoint of both the line segments AB and CD ​

Answer 1

Answer:

I can prove it

Step-by-step explanation:

In ΔOAB and ΔAOD

∠A = ∠B ( ANGLE)

AD = BC ( SIDE )

∠C = ∠D (ANGLE)

Acc. to ASA congruence ΔAOD  and ΔBOC

AO = OB (CPCT)

CO = OD (CPCT)

{ ∵ CPCT : Corresponding Parts Of Congruent Triangles }

HENCE PROVED

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